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49x^2-56x+16=289
We move all terms to the left:
49x^2-56x+16-(289)=0
We add all the numbers together, and all the variables
49x^2-56x-273=0
a = 49; b = -56; c = -273;
Δ = b2-4ac
Δ = -562-4·49·(-273)
Δ = 56644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{56644}=238$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-238}{2*49}=\frac{-182}{98} =-1+6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+238}{2*49}=\frac{294}{98} =3 $
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